# Questions

My comments and analysis of graphics overview of the 12th's motions. It raises the following questions [as of January 2, 1999] in my mind.

Reference "side view" figure 2
With an entry angle of 32 degrees to the earth orbital plane, how can the 12th get any closer to earth than 22 Million miles? I calculated using a computer drawing package a distance of 44 million miles from 12 Th. to earth as it passes though the Earth's orbital plane with a 32 degree entry angle. The 22 Million miles is assuming it would pass directly over the top of earth. If it travels off to one side or another, then this distance is even greater. The 32 degrees is referenced in numerous places and also is the sum of 11 degree and 21 degree in Figure 1 that shows the 12th orbit. I suspect something is incorrect with the triangle, or the angle, or my understanding.

Reference Top View figure 2
Now if one factors out the above 32 degrees and looks at the angle the 12th makes with in the earth's orbital plane. This angle needs to be a minimum of 22 to 40 degrees to give a 14 million mile close approach. It also needs to be greater than zero degrees to get around the sun. This drawing says the 12th would need to be coming in from a direction that is off by 2-4 (9h-13h) or more hours from the direction it should be coming from (green arrow). Could it be there is something we don't understand about the orientation or size of the entry triangle?